8x^2+-200x+800=0

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Solution for 8x^2+-200x+800=0 equation:



8x^2+-200x+800=0
We add all the numbers together, and all the variables
8x^2-200x=0
a = 8; b = -200; c = 0;
Δ = b2-4ac
Δ = -2002-4·8·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-200}{2*8}=\frac{0}{16} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+200}{2*8}=\frac{400}{16} =25 $

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